The phenotypic ratio of the cross is as follows: 3 red antennas: 1 white antenna
For question 2, the phenotypic ratio of the F2 generation is: 3 black-eyed: 1 orange-eyed
QUESTION 1
According to the first question, a gene coding for antenna color in butterflies is involved. Red antennas (“R”) is dominant to white antennas (“r”). Hence, a butterfly with genotype "Rr" will be phenotypically red.
According to this question, If both parents are heterozygous for red antennas i.e. Rr (red antenna) × Rr (red antenna), the following gametes will be produced: R and r. Using these gametes in a punnet square (see attached image), the following phenotypic ratio of offspring is produced:
3 RED ANTENNAS (RR, Rr, Rr) : 1 WHITE ANTENNA (rr)
2. In the second question, all the offspring of a cross between a black-eyed mendelien (BB) and an orange-eyed mendelien (bb) have black eyes (Bb). In a cross between two F1 black-eyed mendeliens i.e. Bb × Bb, the following proportion of offspring is produced:
BB, Bb, Bb, bb
Hence, a phenotypic ratio of 3 black-eyed: 1 orange-eyed
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