Answer:
By comparing of elements of both matrices, we will get,
[tex]x + y = 5 \: \: \: - - - (1) \\ \sf \: and \\ x - 2 = 3 \\ = > x = 3 + 2 \\ = > \green{ \boxed{x = 5}} \\ \\ so \: \: from \: eqn.(1) \\ 5 + y = 5 \\ = > y = 5 - 5 \\ = > \green{ \boxed{ y = 0}}[/tex]
[tex]\large \green{ \: \: \: \: \boxed{\boxed{\begin{array}{cc} \sf \: mark \: \\ me \: as\\ \bf \: brainliest \: \end{array}}}} \\ [/tex]
