Area of rhombus = 1/2 × d1 × d2
Let the other diagonal be x
ATQ
1/2 × 18 × x = 24
9 × x = 24
x = 24/9
x = 8/3
Now half each diagonal = 9 and 4/3
Now side = b² + p² = h²
9²+(4/3)² = h²
81 + 16/9 = h²
729/9 + 16/9 = h²
745/9 = h²
√(745/9) = h
Therefore the side of the rhombus is √(745/9)cm
Answered by Gauthmath must click thanks and mark brainliest