Respuesta :

Solution:-10

As <AGQ and <EQG are corresponding interior angles

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 60°+a=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow a=180-60[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow a=120}[/tex]

  • <AGQ=<PQR=60°
  • <BHF=<PRQ=75°

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow b=75°}[/tex]

According to angle sum property

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow b+c+<PQR=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+75+60=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+135=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c=180-135[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow c=45°}[/tex]

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