Question

Two angles of a triangle have the same measure and the third one is 48 degrees greater than the measure of each of the other two. Find the measure of the LARGEST angle in the triangle.

Answer 1

Let the two equal angles each be x

Let the third angle be x + 48

Then ATQ

x + x + x + 48 = 180

3x + 48 = 180

3x = 180 - 48 (Angle Sum Property)

3x = 132

x = 132/3

x = 44

Now the two angles are each 44

And the largest angle = 44 + 48

= 92

Answered by Gauthmath must click thanks and mark brainliest

Answer 2

Largest angle in the triangle is $92^{0}$

What is triangle?

"A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry."

What is angle sum property?

"Angle sum property of triangle states that the sum of interior angles of a triangle is 180°."

Let us assume the two equal angles be '$x$'

According to the question,

Two equal angles = $x$

Third angle = $x+48^{0}$

We know the angle sum property

$x+x+x+48^{0} =180^{0}$

⇒$3x+48^{0}=180^{0}$

⇒$3x=180^{0}-48^{0}$

⇒$x=\frac{132^{0} }{3}$

⇒$x=44^{0}$

Two equal angles  $x$ = $44^{0}$

Largest Angle = $44^{0} +48^{0}$

∴  Largest Angle = $92^{0}$

Hence, Largest Angle = $92^{0}$

Learn more about triangle and angle sum property here

https://brainly.com/question/3772264

https://brainly.com/question/4316040

#SPJ2