Question

lus
Find the probability that a randomly
selected point within the circle falls
in the white area.
r = 4 cm
4 √2cm
[? ]%

Answer 1

Answer:

1-$\frac{2 }{\pi }$ = 1- .64 = .36 = 36%

$(4\sqrt{2}) ^{2} = 32$

$\pi 4^{2}$= 16$\pi$

$\frac{32}{16\pi }$= $\frac{2 }{\pi }$

Step-by-step explanation: