The answers required to complete the proof are:
1. The expression for length of side AZ would be in terms of x, y and z.
2. An expression for the length of side AY would be in terms of z and X.
3. He can use the trigonometric functions to relate x, y, z and X.
NB: Only the trigonometric functions can be used to relate the three sides of a given triangle with any of its angles.
4. The required angle is <X.
From the given question, the following can be derived:
1. To determine AZ applying the required trigonometric function to ΔXYZ, to have;
Cos(X) = [tex]\frac{z}{y}[/tex]
y = [tex]\frac{z}{Cos(x) }[/tex]
But, Cos (X) = [tex]\frac{AX}{z}[/tex]
AX = zCos(X)
Thus,
y = AX + AZ
So that,
AZ = y - AX
= y - zCos(X)
AZ = y - zCos(X)
The length of side AZ can be expressed in terms of x, y and z.
2. From Δ XYA, apply the Pythagoras theorem to have;
[tex]/Hyp/^{2}[/tex] = [tex]/Adj 1/^{2}[/tex] + [tex]/Adj 2/^{2}[/tex]
[tex]z^{2}[/tex] = [tex](AX)^{2}[/tex] + [tex](AY)^{2}[/tex]
But;
zCos(x) = AX
So that;
[tex]z^{2}[/tex] = [tex](zCos(X))^{2}[/tex] + [tex](AY)^{2}[/tex]
This implies that;
AY = [tex]\sqrt{z^{2} - (zCos(X))^{2} }[/tex]
The student should write the length of AY in terms of z and X.
3. The student can use the trigonometric functions to relate x, y, z and X.
NB: Only the trigonometric functions can be used to relate the three sides of a given triangle with any of its angles.
4. The reference angle to the three sides of Δ XYZ would be X.
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