in order for the parallelogram to be a rhombus, x=?

[tex]\\ \large\sf\longmapsto x + 15 = 2x - 40 \\ \\ \large\sf\longmapsto x - 2x = - 40 - 15 \\ \\ \large\sf\longmapsto - x = - 55\\ \large\sf\longmapsto x = 55[/tex]
The value of x is 55 degrees.
A rhombus is a diamond-shaped quadrilateral that has all four sides equal
The properties of a rhombus are:
According to the given question.
We have a rhombus.
Since, we know that the diagonals of the rhombus bisect the angles.
Therefore,
[tex](x+15)^{o} = (2x-40)^{o}[/tex]
Solve, the above expression for x.
[tex]\implies x +15 = 2x -40\\\implies 15+40 = 2x -x \\\implies 55 = x \\0r\ x = 55^{o}[/tex]
Hence, the value of x is 55 degrees.
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