Answer:
The solution of this expression is [tex]x_{1} = -1[/tex] and [tex]x_{2} = -\frac{1}{2}[/tex].
Step-by-step explanation:
The procedure for solution of exercise A is described below:
1) We expand the expression.
2) The resulting expression is rearranged into the form of a second order polynomial.
3) Roots are found by Quadratic Formula.
Step 1:
[tex]2\cdot x \cdot (x+1.5) = -1[/tex]
[tex]2\cdot (x^{2}+1.5\cdot x) = -1[/tex]
[tex]2\cdot x^{2} + 3\cdot x = -1[/tex]
Step 2:
[tex]2\cdot x^{2}+3\cdot x +1 = 0[/tex]
Step 3:
[tex]x_{1, 2} = \frac{-3\pm \sqrt{3^{2}-4\cdot (2)\cdot (1)}}{2\cdot (2)}[/tex]
[tex]x_{1,2} = -\frac{3}{4}\pm \frac{1}{4}[/tex]
[tex]x_{1,2} = \frac{-3\pm 1}{4}[/tex]
The solution of this expression is [tex]x_{1} = -1[/tex] and [tex]x_{2} = -\frac{1}{2}[/tex].
