Question

A motorcycle starts from rest and gains a velocity of 40m/s in 8 seconds. Find (i) acceleration and (ii) distance travelled by the motorcycle.​

Answer 1

Answer:

• Initial velocity (u) = 0 m/s

• Final velocity (v) = 40 m/s

• time (t) = 8s

Acceleration :

$\implies \sf a = \dfrac{\Delta v}{ t}$

$\implies \sf a = \dfrac{v - u}{ t}$

$\implies \sf a = \dfrac{40 - 0}{ 8}$

$\implies \sf a = \dfrac{40}{ 8}$

$\implies \bf a = 5 \: {ms}^{ - 2}$

• Distance travelled by the motorcycle:

$\longrightarrow \sf {v}^{2} - {u}^{2} = 2as$

$\longrightarrow \sf {(40)}^{2} - {(0)}^{2} = 2 \times5 \times s$

$\longrightarrow \sf 1600 = 10s$

$\longrightarrow \sf s = \dfrac{1600}{10}$

$\longrightarrow \bf s = 160 \: m$