Answer:
[tex]y = -\frac{2}{3}x + 2[/tex]
Step-by-step explanation:
The question is incomplete, as the graphs or equations of the lines are not given.
However, I will give a general explanation of calculating both intercepts
A linear equation is of the form:
[tex]y = mx + b[/tex]
Where:
[tex]b \to[/tex] y intercept
So, the equation
[tex]y = -\frac{2}{3}x + 2[/tex]
has 2 as its y-intercept
Set y to 0, to calculate the x-intercept
[tex]0 = -\frac{2}{3}x + 2[/tex]
Collect like terms
[tex]\frac{2}{3}x = 2[/tex]
Multiply by 3/2
[tex]x = 2 * \frac{3}{2}[/tex]
[tex]x = 3[/tex]
So, the equation with the required criteria is:
[tex]y = -\frac{2}{3}x + 2[/tex]