Answer:
Quadrant 2
Step-by-step explanation:
Given
[tex]\theta = 115^o[/tex]
Required
The quadrant
We have:
[tex]0^o < \theta < 90^o[/tex] --- quadrant 1
[tex]90^o < \theta < 180^o[/tex] --- quadrant 2
[tex]180^o < \theta < 270^o[/tex] --- quadrant 3
[tex]270^o < \theta < 360^o[/tex] --- quadrant 4
So, by comparison; we have:
[tex]90^o < \theta < 180^o[/tex]
Substitute 115 for [tex]\theta[/tex]
[tex]90^o < 115 < 180^o[/tex]
The above is true for quadrant 2
