Can someone help me with this

Answer:
Step-by-step explanation:
The standard form for a circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex] and what's important here is that the x- and the y- remain that way in the equation. Filling in our values,
[tex](x-(6))^2+(y-(-3))^2=25[/tex] which tells us that our center is
6 and -3 -------------------> (6, -3)
The radius is the square root of 25 which is 5.