Can someone help me with this

Answer:
Step-by-step explanation:
The formula for this, specific to our circle, is
∠RQP = [tex]\frac{1}{2}[/tex](arc SP - arc RP) and filling in:
∠RQP = [tex]\frac{1}{2}(170-86)[/tex] and
∠RQP = [tex]\frac{1}{2}(84)[/tex] so
∠RQP = 42°