Answer:
Step-by-step explanation:
Let the initial velocity of the ball is u.
At the maximum height the speed is zero.
Let the time is t.
Use first equation of motion.
v = u - gt
0 = u - g t
t = u/g
Let the maximum height is H.
Use third equation of motion
[tex]v^2 = u^2 - 2 gh\\\\0 = u^2 - 2 gH\\\\H = \frac{u^2}{2 g}[/tex]