Answer:
56%
Explanation:
If I use 25 grams of iron (III) phosphate and obtain 18.5 g of iron (III) sulfate, what is my percent yield?
Step 1: Write the balanced equation
2 FePO₄ + 3 Na₂SO₄ ⇒ Fe₂(SO₄)₃ + 2 Na₃PO₄
Step 2: Calculate the theoretical yield of Fe₂(SO₄)₃
The mass ratio of FePO₄ to Fe₂(SO₄)₃ is 301.64:399.88.
25 g FePO₄ × 399.88 g Fe₂(SO₄)₃/301.64 g FePO₄ = 33 g Fe₂(SO₄)₃
Step 3: Calculate the percent yield of Fe₂(SO₄)₃
We will use the following expression.
%yield = (experimental yield/theoretical yield) × 100%
%yield = (18.5 g/33 g) × 100% = 56%
