Answer:
The answer is "3.27%"
Explanation:
[tex]P = \$ 22,000\\\\t = 1.5\\\\I= \$ 1,100\\\\A=P+I=\$22,000+1,100=\$ 23,100\\\\n = 4\\\\[/tex]
Using formula:
[tex]\bold{A=P(1+\frac{r}{n})^{nt}}\\\\[/tex]
[tex]23,100=22,000(1+\frac{r}{4})^{4\times 1.5}\\\\23,100=22,000(1+\frac{r}{4})^{6}\\\\\frac{23,100}{22,000}=(1+\frac{r}{4})^{6}\\\\1.05=(1+\frac{r}{4})^{6}\\\\1.05^{\frac{1}{6}}=(1+\frac{r}{4})\\\\1.008164846=(1+\frac{r}{4})\\\\1.008164846-1=\frac{r}{4}\\\\0.008164846=\frac{r}{4}\\\\r=0.008164846\times 4\\\\r=0.03266\\\\r=3.266\% \approx 3.27\%[/tex]