Answer: x= 6 +/- root of 7
Step-by-step explanation:
1. Expand the left hand side: e.g, 3^2 = 3×3 =9
(x-6)(x-6) = 7
2. Multiply the brackets first by "separating" one of them, and take 7 to the left hand side:
x(x-6) - 6(x-6) =7
x^2 - 6x -6x +36-7=0
Simplify by adding like terms
x^2 -12x +29=0
3.Now your equation is in the form ax^2+bx + c =0, it means you can use the quadratic formula which is x= [-b +/- root of (b^2 - 4ac)]÷ 2a
Then SUBSTITUTE where:
a=1
b= -12
c=29
Therefore, x should be 6+ root of 7 OR 6- root of 7
