Answer:
Stationary matrix S = [ 0.6 0.4 ]
limiting matrix P = [tex]\left[\begin{array}{ccc}0.6&0.4\\0.6&0.4\\\end{array}\right][/tex]
Step-by-step explanation:
Transition matrix
[tex]p = \left[\begin{array}{ccc}0.8&0.2\\0.3&0.7\\\end{array}\right][/tex]
solving the equation SP = S ( using Markova chain with 2 states )
stationary matrix, S = [ a , 1 - a ]
given that SP = S
[ a , 1 - a ] * [tex]\left[\begin{array}{ccc}0.8&0.2\\0.3&0.7\\\end{array}\right][/tex] = [ a , 1 - a ]
= a*(0.8) + ( 1 - a ) ( 0.3 ) = a
∴ a = 0.6
hence; stationary matrix S = [ 0.6 0.4 ]
limiting matrix P = [tex]\left[\begin{array}{ccc}0.6&0.4\\0.6&0.4\\\end{array}\right][/tex]
