Answer:
-8, 5 , 0 , -7 , 16
Step-by-step explanation:
Given
[tex]t_n = (-1)^{n+1}(n^2 - 9)[/tex]
Required
The first five terms
When [tex]n = 1[/tex]
[tex]t_1 = (-1)^{1+1}(1^2 - 9)[/tex]
[tex]t_1 = (-1)^{2}(1 - 9)[/tex]
[tex]t_1 = -8[/tex]
When [tex]n =2[/tex]
[tex]t_2 = (-1)^{2+1}(2^2 - 9)[/tex]
[tex]t_2 = (-1)^3 * (4 - 9)[/tex]
[tex]t_2 = 5[/tex]
[tex]t_3 = (-1)^{3+1}(3^2 - 9)[/tex]
[tex]t_3 = (-1)^{4}(9 - 9)[/tex]
[tex]t_3 = 0[/tex]
[tex]t_4 = (-1)^{4+1}(4^2 - 9)[/tex]
[tex]t_4 = (-1)^5(16 - 9)[/tex]
[tex]t_4 = -7[/tex]
[tex]t_5 = (-1)^{5+1}(5^2 - 9)[/tex]
[tex]t_5 = (-1)^{6}(25 - 9)[/tex]
[tex]t_5 = 16[/tex]
So, the first five terms are: -8, 5 , 0 , -7 , 16