Respuesta :
We need to form a system of equations:
3x + 2y = 2
2x + 3y = 4
Now, we can multiply the first equation by 2, and the second equation by 3, to even out the coefficients by the variables (to make them the same thing).
6x + 4y = 4
6x + 9y = 12
Next, we can subtract the second equation from the first. We get:
0x - 5y = -8
Then this becomes:
-5y = -8
÷-1 ÷-1
5y = 8
÷5 ÷5
y = 1.6
Substitute 1.6 for y in one of the equations:
2x + 3(1.6) = 4
2x + 4.6 = 4
2x = -0.6
÷2 ÷2
x = -0.3
Answer: [tex]\Large \boldsymbol{(-0,4 \ \ ; \ \ 1,6)}[/tex]
Step-by-step explanation:
[tex]\displaystyle \Large \boldsymbol{} - \left \{ {{3x+2y=2} \ \ |\times3\atop {2x+3y=4}\ \ |\times2} \right. => \\\\\\\ 9x-4x+6y\!\!\!\!\!\!\diagup-6y\!\!\!\!\!\!\diagup=6-8 \\\\5x=-2 \\\\x=-0,4 \ \ ; \ \ y=(2+1,2):2 =1,6[/tex]