option D makes no sense, logical contradiction there. x can't be less than 1 and greater than 4 at the same time.
a root must at least be zero, but decide by zero is also not allows. so the root on the right side must get bigger than zero.
this means x must stay below 1
the left part must at least be zero under the root to have a solution, so x must be bigger than -4 or equal to -4.
go with
[tex] - 4 \leqslant x < 1[/tex]
