Question

What is y-3=3/4(x-5) in standard form?

Answer 1

Answer:

$y-3=\frac{3}{4} (x-5)\\\\y-3=\frac{3}{4}x-\frac{3}{4}(5)\\\\y=\frac{3}{4} x+3-\frac{15}{4} \\\\y=\frac{3}{4} x+\frac{12}{4} -\frac{15}{4} \\\\y=\frac{3}{4} x-\frac{3}{4}$

Is this standard form? :\

Answer 2

Answer:

3x-4y=3

Step-by-step explanation:

Hi there!

We are given the equation y-3=$\frac{3}{4}(x-5)$, and we want to write it in standard form

Standard form is given as ax+by=c, where a, b, and c are integer coefficients, a CANNOT be 0 and CANNOT be negative, and b also CANNOT be 0

So let's expand the parentheses in the equation

Do the distributive property

y-3=$\frac{3}{4}x-\frac{15}{4}$

Add 3 to both sides

y=$\frac{3}{4}x-\frac{3}{4}$

We expanded the parentheses, but the equation is now in slope-intercept form (y=mx+b, where m is the slope and b is the y intercept)

Remember that we want it in standard form, which is ax+by=c

Subtract $\frac{3}{4}x$ from both sides

$\frac{-3}{4}x+y=\frac{-3}{4}$

Remember that the coefficients of a, b, and c need to be integers, and also that a (the coefficient in front of x) CANNOT be negative

So multiply both sides by -4

$-4(\frac{-3}{4}x+y)=-4(\frac{-3}{4})$

Distribute -4 to every number

$-4(\frac{-3}{4}x)+-4(y)=-4(\frac{-3}{4})$

Multiply

$\frac{12}{4}x-4y=\frac{12}{4}$

Simplify

3x-4y=3

There's the equation in standard form

Hope this helps!