Question

Use the parabola tool to graph the quadratic function f(x)=−x2+4. Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.

Answer 1

Answer:

see below

Step-by-step explanation:

f(x) = -x^2 +4

The vertex form is

y = a(x-h)^2 +k

Rewriting

f(x) = -(x-0)^2 +4

The vertex is (0,4) and a = -1

Since a is negative we know the parabola opens downward

f(x) = -(x^2 -4)

We can find the zeros

0 = -(x^2 -2^2)

This is the difference of squares

0 = -(x-2)(x+2)

Using the zero product property

x-2 =0   x+2 =0

x=2   x=-2

(2,0)  (-2,0) are the zeros of the parabola and 2 other points on the parabola

We have the maximum ( vertex) and the zeros and know that it opens downward, we can graph the parabola

Answer 2

Answer:

Your vertex is (4,0)

Step-by-step explanation: