Question

Deepta adhivnav having weight 450N and 350N are playing see-saw. Deepta sits at a distance of 2m from the fulcrum, how far should abhinav be seated in order to balance deepta?

Answer 1

Answer:

Explanation:

This is a torque problem where balance is achieved when the sum of the torques equal 0. The equation for torque is

$\tau=F*r$ where F is the force in Newtons that is perpendicular to the lever arm, and r is the length of the lever arm in meters.

450(2) = 350r and

$\frac{450(2)}{350}=r$ so

r = 2.6 m