Question

Which system of inequalities is shown in the graph?
&
A. y 2 X+1
yzx-3x
B. ys X+1
ys 2-3x
O C. ys x+1
yz x2-3x
O D. ys-x+1
ysx2-3x

Answer 1

Answer:

A

Step-by-step explanation:

because when i dentify graph theres y an x

Answer 2

The feasible region of the result is defined by the system of inequalities.

Correct response:

The system of inequalities shown in the graph is given by the option B.

B. y ≤ x + 1

y ≤ x² - 3·x

Methods used to find the system of inequalities

Please find attached the possible graph of the inequality

The possible graph obtained from a similar question has a straight line portion and a quadratic portion.

Points on the straight line are; (0, 1), (3, 4), and (5, 6)

Therefore;

$Slope \ of \ the \ line = \dfrac{6 - 1}{5 - 0} = 1$

Equation of the line is; y - 1 = 1 × x

Therefore;

y = x + 1

The shaded region is below the line which gives;

• y ≤ x + 1

Points on the quadratic graph are; (0, 0), (4, 4), and (2, -2).

The general form of a quadratic equation is; y = a·x² + b·x + c

Therefore, we have;

0 = a × 0 + b × 0 + c

Which gives;

c = 0

4 = a × 4² + b × 4 = 16·a + 4·b

-2 = a × 2² + b × 2 = 4·a + 2·b

4 = 16·a + 4·b...(1)

-2 = 4·a + 2·b...(2)

Multiplying equation (2) by 2 and subtracting from equation (1) gives;

2 × -2 = 2 × (4·a + 2·b) = 8·a + 4·b

-4 = 8·a + 4·b

4 - (-4) = 16·a + 4·b - (8·a + 4·b) = 8·a

8 = 8·a

$a = \dfrac{8 }{8} = 1$

a = 1

-2 = 4 × 1 + 2·b

2·b = -2 - 4 = -6

$b = \dfrac{-6}{2} = \mathbf{ -3}$

Which gives;

y = 1·x² - 3·x = x² - 3·x

The line is a solid line and shaded region is the region under the graph which gives;

• y ≤ x² - 3·x

Therefore;

The inequalities in the graph are given by option B.

B. y ≤ x + 1

y ≤ x² - 3·x

Learn more about graph of inequalities here:

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