Answer:
2nd option
Step-by-step explanation:
Using the sine and cosine ratios in the right triangle
sin82° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{KL}{KM}[/tex] = [tex]\frac{KL}{\sqrt{11} }[/tex] ( multiply both sides by [tex]\sqrt{11}[/tex] )
[tex]\sqrt11}[/tex] × sin82° = KL , then
KL ≈ 3.28 ( to the nearest hundredth )
cos82° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{ML}{KM}[/tex] = [tex]\frac{ML}{\sqrt{11} }[/tex] ( multiply both sides by [tex]\sqrt{11}[/tex] )
[tex]\sqrt{11}[/tex] × cos82° = ML , then
ML ≈ 0.46 ( to the nearest hundredth )
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The sum of the 3 angles in a triangle = 180° , so
∠ K = 180° - (90 + 82)° = 180° - 172° = 8°
