Question

A body starts with an initial velocity of 15m/s and accelerates 4m/s2. Find the distance covered by 5s

Answer 1

Answer:

Distance, S = 110 meters

Explanation:

Given the following data;

Initial velocity = 15 m/s

Acceleration = 4 m/s²

Time = 5 seconds

To find the distance covered, we would use the second equation of motion;

$S = ut + \frac{1}{2} at^{2}$

Where;

S is the distance covered or displacement of an object.

u is the initial velocity.

a is the acceleration.

t is the time.

Substituting the values into the equation, we have;

$S = 15*4 + \frac{1}{2} * 4*5^{2}$

$S = 60 + 2*25$

$S = 60 + 50$

Distance, S = 110 meters