Answer:
D) Q = 80 C
Explanation:
Given;
current flowing in the light bulb, I = 2A
time of current flow, t = 40,000 ms = 40,000 x 10⁻³ s = 40 s
The quantity of the charge is calculated as;
Q = It
where;
Q is the quantity of the charge (Coulombs)
Q = (2 ) x (40)
Q = 80 C
Therefore, the quantity of charge flowing in the circuit is 80 C
D) Q = 80 C
