Question

How many real solutions exist for this system of equations?
y=x^2+4
y= 4x
ОА. .
zero
OB.
one
Ос.
two
OD
infinite
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Answer 1

Answer:

One

Step-by-step explanation:

Set each equations equal to each other

${x}^{2} + 4 = 4x$

${x}^{2} - 4x + 4$

Find the discrimant.

${ - 4 {}^{2} - 4(1)(4) } = 0$

This means there is one real solution. Since the discramnt equal 0.