Question

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 6.90kg of water at 34.7 degrees C . During the reaction 57.1kJ of heat flows out of the bath and into the flask.
Calculate the new temperature of the water bath. You can assume the specific heat capacity of water under these conditions is 4.18J.g^(-1).K^(-1) . Round your answer to significant digits.

Answer 1

Answer:

$T_2= 36.7 \textdegree C$

Explanation:

Mass of Water $m_w=6.90kg$

Temperature $T=34.7 degrees$

Heat Flow $H=57.1kJ$

Specific heat capacity of water $\mu= 4.18J.g^(-1).K^(-1)$

Generally the equation for Final Temperature is mathematically given by

$M*\mu *T_1 + Q = M*\mu *T_2$

$T_2=\frac{M*\mu *T_1 + Q }{M*\mu}$

Therefore

$T_2=\frac{6.90*4.18*34.7 + 57.1}{6.90*4.18}$

$T_2= 36.7 \textdegree C$