Question

Help please 6x + 3 > a if the inequality above is true for the constant a which of the following. coupd be a vakue of z

Answer 1

Answer:

$\frac{a+3}{6}$

Step-by-step explanation:

Treat it like any other math problem with a equals sign:

6x + 3 = a

subtract 3 from both sides: 6x = a + 3

divide both sides by 6: $x = \frac{a+3}{6}$

swap the ≥ back in: $x \geq \frac{a+3}{6}$

the only time the sign flips is if you divide by a negative