Question

1) (30 pts ) Oxygen (O2) flows through a pipe, entering at at 4 m/sec at 10000 kPa, 227oC. For a pipe inside diameter of 3.0 cm, find the volumetric flow rate (m3/sec) and the mass flow rate of the gas (kg/sec) assuming you have an ideal gas

Answer 1

Complete Question

Nitrogen (N2) flows through a pipe, entering at at 4 m/sec at 1000 kPa, 2270C. For a pipe inside diameter of 3 cm, find the volumetric flow rate (m3/sec) and the mass flow rate of the gas (kg/sec) assuming you have an ideal gas Then using your ideal gas mass flow rate find the rate at which enthalpy enters the pipe (kJ/sec) NO Cp, Cv, k permitted

Answer:

$H=9.91kJ/sec$

Explanation:

From the question we are told that:

Velocity $v=4 m/sec$

Pressure $P=1000kPa$

Temperature $T=227 \textdegree C$

Diameter $d=3cm=>0.03m$

Generally the equation for volumetric Flow Rate is mathematically given by

$V_r=(\frac{\pi*d^2}{4}v)$

$V_r=(\frac{\pi*(0.03)^2}{4} *4)$

$V_r=0.002827m^3/s$

Generally the equation for mass Flow Rate is mathematically given by

$m_r=\frac{PV_r}{RT}$

$m_r=\frac{1000*0.002827}{0.297*(227+273)}$

$m_r=0.019kg/sec$

Generally the equation for mass Flow Rate is mathematically given by

Using gas Table for enthalpy Value

$T=500K=>h=520.75kg$

Therefore

$H=mh$

$H=0.019*520.75$

$H=9.91kJ/sec$