Find the missing length of the following trapezoid
![Find the missing length of the following trapezoid class=](https://us-static.z-dn.net/files/de2/a9dea128bc065274782de5b1addd7f2f.png)
Answer:
1) The length of [tex]DC[/tex] is 20.
2) The length of [tex]PS[/tex] is 17.
Step-by-step explanation:
1) If [tex]DR = RE[/tex] and [tex]CS = SB[/tex], then we can use the following proportionality ratio:
[tex]\frac{DE}{DR} = \frac{32 - x}{26 - x}[/tex] (1)
Where [tex]x[/tex] is the length of segment [tex]\overline{CD}[/tex].
If [tex]DE = 2\cdot DR[/tex], then the value of [tex]x[/tex] is:
[tex]2 = \frac{32-x}{26-x}[/tex]
[tex]52 - 2\cdot x = 32 - x[/tex]
[tex]20 = x[/tex]
The length of [tex]DC[/tex] is 20.
2) If [tex]QV = VP[/tex] and [tex]RW = WS[/tex], then we can use the following proportionality ratio:
[tex]\frac{QP}{QV} = \frac{x-7}{12-7}[/tex] (2)
Where [tex]x[/tex] is the length of segment [tex]\overline{PS}[/tex].
If [tex]QP = 2\cdot QV[/tex], then the value of [tex]x[/tex] is:
[tex]2 = \frac{x-7}{5}[/tex]
[tex]10 = x-7[/tex]
[tex]x = 17[/tex]
The length of [tex]PS[/tex] is 17.