Question

Given a triangle MTN, prove that
<m+<t+<n= 180° strictly
use m, T and N with other
Letters in your triangle.​

Answer 1

Answer:

$\angle m + \angle t + \angle n = 180$

Step-by-step explanation:

Required

Show that:

$\angle m + \angle t + \angle n = 180^o$

To make the proof easier, I've added a screenshot of the triangle.

We make use of alternate angles to complete the proof.

In the attached triangle, the two angles beside $\angle m$ are alternate to $\angle t$ and $\angle n$

i.e.

$\angle 1 = \angle t$

$\angle 2 = \angle n$

Using angle on a straight line theorem, we have:

$\angle 1 + \angle m + \angle 2 = 180$

Substitute values for (1) and (2)

$\angle t + \angle m + \angle n = 180$

Rewrite as:

$\angle m + \angle t + \angle n = 180$ -- proved