Question

- Mean test score was 200 with a standard deviation of 40- Mean number of years of service was 20 years with a standard deviation of 2 years.In comparing the relative dispersion of the two distributions, what are the coefficients of variation

Answer 1

Answer:

The correct answer is "Test 20%, Service 10%".

Step-by-step explanation:

As we know,

The coefficient of variation (CV) is:

⇒ $CV=\frac{Standard \ deviation}{Mean}\times 100$

Now,

CV of test will be:

= $\frac{40}{200}\times 100$

= $20$ (%)

CV of service will be:

= $\frac{2}{20}\times 100$

= $10$ (%)