Question

Ignore friction. A 20. Lb. Object was lifted to a height of 10 feet by a force of 30. Lb. (a) How much work (ft.Lb) is done by the force? (b) Find the change in potential energy (ft.Lb) of the object

Answer 1

a)
W = Fd
W = (30Lb)(10 ft)
W = 300ft.Lb

b)
work-energy theorem: W = ∆E
∆E = 300ft.Lb

Answer 2

(a) The work done by force in lb-ft is 300 lb-ft.

(b) The change in potential energy of the object is 200 lb-ft.

Work done by force

The work done by force in lb-ft is calculated as follows;

W = Fd

W = 30 x 10

W = 300 lb-ft

Change in potential energy

The change in potential energy of the object is calculated as follows;

ΔP.E = P.Ef - P.Ei

ΔP.E = 20 x 10 - 0 = 200 lb-ft

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