Question

please help!! i have no idea!

Answer 1

Answer:

θ = 60.34

Step-by-step explanation:

$\frac{\left(12.8\cdot \:sin\left(90\right)\right)}{sin\left(52.3\right)}$ = 16.177

$\frac{\left(16.177\cdot \:sin\left(90\right)\right)}{18.6}$ =  θ = .869

$arcsin\left(.869\right)$ = 60.34

Answer 2

Answer:

60.4°

Step-by-step explanation:

There are two right triangles.

One right triangle (on the left side) has an acute angle measuring 52.3°.

Its opposite leg measures 12.8 cm.

We can find the length of its hypotenuse, x.

sin 52.3° = opp/hyp

sin 52.3° = 12.8 cm/x

x * sin 52.3° = 12.8 cm

x = 12.8 cm/sin 52.3°

x = 16.2 cm

Now we use the hypotenuse of the left side triangle which is a leg of the right side triangle.

For the right side triangle, we are looking for angle Θ. We know the opposite leg, 16.2 cm and the hypotenuse, 18.6 cm.

sin Θ = opp/hyp

sin Θ = 16.2/18.6

sin Θ = 0.8698

Θ = sin^-1 0.8698

Θ = 60.4°