Question

What is the concentration of HI in the final solution when 65 mL of a 3.0 M HI solution is diluted with pure water to a total volume of 0.15 L g?

Answer 1

Answer:

The concentration of HI in the final solution is 1.3 M.

Explanation:

Dilution is the reduction in concentration of a chemical in a solution. It is achieved by adding more solvent to the same amount of solute.

In other words, in a dilution, the amount of solute does not change, but the volume of the solvent does: as more solvent is added, the concentration of the solute decreases, since the volume (and weight) of the solution increases.

When dealing with dilution you will use the following equation:

C1*V1= C2*V2

• C1 = initial concentration
• V1 = initial volume
• C2 = final concentration
• V2 = final volume

In this case:

• C1 = 3 M
• V1 = 65 mL= 0.065 L (being 1000 mL= 1 L)
• C2 = ?
• V2 = 0.15 L

Replacing:

3 M* 0.065 L= C2*0.15 L

Solving:

$C2=\frac{3 M*0.065 L}{0.15 L}$

C2= 1.3 M

The concentration of HI in the final solution is 1.3 M.