Total length of cable required is 466.18 m.
Pythagoras theorem states that In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides.
According to the question
A 100m mast is supported by six cables in two sets of three cables.
They are anchored to the ground at an equal distance from the mast.
The top set of three cables is attached at a point 20m below the top of the mast.
Each cable in the lower set of three cables is 60m long and is attached at a height of 30m above the ground.
One set of guy wires (1 upper and one lower have two right triangles which can solve
The lower right triangle
a = distance from the pole to guy tie point
b = 30 m
c = 60 m the lower guy wire (the hypotenuse)
Using Pythagoras theorem
[tex]a^{2} +30^{2} =60^{2}[/tex]
⇒ [tex]a^{2} = 3600 - 900[/tex]
⇒ [tex]a^{2} =2700[/tex]
⇒ [tex]a = \sqrt{2700}[/tex]
⇒ [tex]a = 51.96[/tex] m from the pole to the tie point.
The other triangle using upper guy wire as the hypotenuse (h) tied to a point on the pole 80 m from the ground (20 m from the top) and also 50m from the tie point.
Using Pythagoras theorem
[tex]h^{2} =(51.96)^{2} +80^{2}[/tex]
⇒ [tex]h^{2}=2700+6400[/tex]
⇒ [tex]h^{2}=9100[/tex]
⇒ [tex]h = \sqrt{9100}[/tex]
⇒ [tex]h = 95.39[/tex] m , the length of the upper guy wire
For one set of guy wires (1 upper & 1 lower):
= 95.39 + 60
= 155.39 m
For 3 sets of guy wires :
= 3(155.39)
= 466.18 m of wire required
Hence, total length of cable required is 466.18 m.
Find out more information about Pythagoras theorem here
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