QUESTION:- DETERMINE THE X-INTERCEPT AND THE Y-INTERCEPT FOR THE GRAPH OF THE EQUATION.
EQUATION:- 2x - 3y + 36 = 0
STANDARD EQUATION:- y=mx+c
where
- m-> slope.
- c-> Y-INTERCEPT
- x&y are the coordinates.
SO GIVEN EQUATION:- 2x - 3y + 36 = 0
WE CAN SOLVE THIS TO CHANGE IN FORMAT OF STANDARD EQUATION
[tex]2x - 3y + 36 = 0 \\ 2x + 36 =3y \\ y = \frac{2}{3} x + \frac{36}{3} \\ y = \frac{2}{3} x + \frac{ \cancel{36}^{ \: \: 12} }{ \cancel3} \\ y = \frac{2}{3} x + 12 \\ [/tex]
SO :-
[tex]m = \frac{2}{3} \\ y - intercept = 12 \: ans[/tex]
[tex]slope = \frac{y2 - y1}{x2 - x1} \\ \frac{2}{3} = \frac{0 - 12}{x - 0} \\ 2x = ( - 12) \times 3 \\ x = \frac{ - \cancel{12}^{ \: \: 6} \times 3 }{ \cancel{2}} \\ x = - 18 \: \: ans[/tex]
