Given:
The graph of a linear inequality.
The boundary line passes through the points (0,-2) and (1,1), and the shaded region lies above the boundary line.
To find:
The inequality for the given graph.
Solution:
The boundary line passes through the points (0,-2) and (1,1), so the equation of the boundary line is:
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-(-2)=\dfrac{1-(-2)}{1-0}(x-0)[/tex]
[tex]y+2=\dfrac{1+2}{1}(x)[/tex]
[tex]y+2=3x[/tex]
Subtract 2 from both sides.
[tex]y=3x-2[/tex]
The boundary line is a solid line and the shaded area lies above the boundary line, so the sign of inequality must be [tex]\geq [/tex].
[tex]y\geq 3x-2[/tex]
Therefore, the required inequality is [tex]y\geq 3x-2[/tex].