Question

give a coordinates of the Vertex y =(x + 2)
.

squared - 1​

Answer 1

Given:

The equation of a parabola is:

$y=(x+2)^2-1$

To find:

The coordinates of the vertex of the given equation.

Solution:

The vertex form of a quadratic function is:

$y=a(x-h)^2+k$               ...(i)

Where, a is a constant and (h,k) is the vertex.

We have,

$y=(x+2)^2-1$                 ...(ii)

On comparing (i) and (ii), we get

$a=1$

$h=-2$

$k=-1$

We know that the vertex of the parabola is (h,k).

Therefore, the vertex of the given equation is (-2,-1).