Question

I do not understand this and could use help it needs the work shown

Answer 1

Answer:

a = 9

Step-by-step explanation:

The given trinomial is :

$x^2-6x+\_\_\__$

let the blank is a.

So, we need to find the value of a so that it results in a perfect square trinomial.

We know that, $(m-n)^2=m^2-2mn+n^2$

So,

$x^2-6x+a=x^2-2(1)(3)+3^2\\=(x-3)^2$

So, the value of a is 9. If a is 9, then only it would be a perfect square trinomial.