Explanation:
The mass of a pot is 300g and contains 90% aluminum. Find the number of moles of aluminum in the pot. P.A. (Al = 27)
The mass of aluminum present in the pot is:
[tex]300 g * 90/100\\=270 g[/tex]
Hence, in the given pot 270g Al is present.
[tex]Number of moles of Al=\frac{given mass ofAl}{its molar mass}[/tex]
The gram atomic mass of Al -27 g/mol
Given the mass of Al is 270 g
Substitute these values in the above formula:
[tex]Number of moles of Al=\frac{given mass ofAl}{its molar mass}\\=\frac{270 g}{27 g} \\=10.0 mol[/tex]
Answer is 10.0 mol of Al is present.