Question

What is the density of ammonia (NH3) at 273 K and 1.00 atm?

A - 0.7601 g/L

B - 0.982 g/L

C - 1.23 g/L

D - 2.43 g/L

Answer 1

Answer:

0.7602 g/L

Explanation:

We'll begin by calculating the molar mass of NH₃. This can be obtained as follow:

Molar mass of NH₃ = 14.01 + (3×1.01)

= 14.01 + 3.03

= 17.04 g/mol

Finally, we shall determine the density of ammonia, NH₃. This can be obtained as follow:

Temperature (T) = 273 K

Pressure (P) = 1 atm

Molar mass of NH₃ (M) = 17.04 g/mol

Gas constant (R) = 0.0821 atm.L/Kmol

Density (D) =?

D = PM / RT

D = (1 × 17.04) / (0.0821 × 273)

D = 17.04 / 22.4133

D = 0.7602 g/L