Step-by-step explanation:
6a. Both the x and y coordinates are negative so this means isn't must be in the Third Quadrant.
6b. The measure of this using the unt circle is
[tex] \cos(x) - \frac{1}{2} [/tex]
[tex] \sin(x) = - \frac{ \sqrt{3} }{2} [/tex]
In the unit circle, this occurs about
an angle of 240 degrees. We can find coterminal angles within the interval of 2 pi to -2 pi. Just subtract 260 from theta.( which is 240)
[tex]240 - 360 = - 120[/tex]
So the angles in the interval is
240, -120.
6c. pi/2 is the same as 90 degrees so this means that
[tex](240 + 90) = 330[/tex]
In the unit circle, we know that at 330 degrees,
[tex] \cos(330) = \frac{ \sqrt{3} }{2} [/tex]
[tex] \sin(330) = \frac{1}{2} [/tex]
So the coordinates are
(sqr root of 3/2, 1/2).
6d. pi is the same as 180 degrees so this means that
[tex](240 - 180) = 60[/tex]
In the unit circle, we know that 60 degrees,
[tex] \cos(60) = \frac{1}{2} [/tex]
[tex] \sin(60) = \frac{ \sqrt{3} }{2} [/tex]
So the coordinates are
(1/2, sqr root of 3/2)
