Question

A sonar pulse has a wavelength of 3.2 cm and a speed of 1,500 m/s in water. What is the frequency of the pulse? (

Answer 1

Explanation:

The universal wave equation states that the velocity of a wave is the product of its wavelength and its frequency.

Mathematically speaking,

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

v

=

λ

f

a

a

∣

∣

−−−−−−−−−−−

where

−−−−−

:

v

=

velocity of wave (metres per second)

λ

=

wavelength (metres)

f

=

frequency (hertz or reciprocal seconds)

Step 1

Convert the given wavelength from centimetres into metres.

3.0

i

c

m

×

m

100

i

c

m

=

3.0

c

m

×

m

100

c

m

=

0.030

i

m

Step 2

Rearrange for frequency,

f

, in the universal wave equation.

v

=

λ

f

Becomes,

f

=

v

λ

Step 3

Substitute your known values to solve for the frequency of the pulse.

f

=

1500

i

m

s

0.030

i

m

f

=

50000

i

H

z

Rounding off the value to two significant figures,

f

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

5.0

×

10

4

i

H

z

a

a

∣

∣

−−−−−−−−−−−−−−−−

Answer 2

The frequency of the pulse is 4.6×$10^4$, when the wavelength of the sonar pulse is 3.2cm. and has a speed of 1,500 m/s in water.

What do you mean by Sonar?

The sonar may be defined as a device that is used to find the distance, direction, and speed of underwater objects like water hills, valleys, icebergs, submarines, sunken ships, etc.

The universal wave equation states that the velocity of a wave is equal to the products of its wavelength and frequency.

   v = λf

∴ f = v/λ

1500/0.032 = 46,875 Hz.

f = 4.6×$10^4$ Hz.

Therefore, the frequency of the pulse is 4.6×$10^4$, when the wavelength of the sonar pulse is 3.2cm. and has a speed of 1,500 m/s in water.

To learn more about Sonar, refer to the link:

https://brainly.com/question/14090821