Question

A right cone has a slant height of 20 feet and the diameter of the base is 24 feet. Find the height of the right cone.

Answer 1

Step-by-step explanation:

Using Pythagoras theorem:

$= \sqrt{{20}^{2} - {12}^{2} }$

$= \sqrt{400 - 144}$

$= \sqrt{256}$

$= 16$