Question

Suppose a triangle has sides a, b, and c, and that a2 + b2 > c2. Let 0/ be the
measure of the angle opposite the side of length c. Which of the following
must be true? Check all that apply.
A. 0/ is an acute angle.

B. cos 0/ > 0

C. The triangle is a right triangle.

D. The triangle is not a right triangle.

Answer 1

Hello,

Answer A

Indeed:

$c^2=c^2+b^2-2ab*cos(\theta) < a^2+b^2\\\\-cos(\theta)<0\\\\cos(\theta)>0\ \Longrightarrow \theta < 90^o$

Answer 2

True statements are:

A.  $\theta$ is an acute angle.

C. The triangle is a right triangle.

D. The triangle is not a right triangle.

What is angle?

An angle is a combination of two rays (half-lines) with a common endpoint.

Given:

a² + b² > c²

as, the triangle with sides a, b and c.

If this is a right triangle, then the condition a² + b² > c² apply.

Using cosine law.

angle> 90 degrees which is an obtuse angle.

Also, cos $\theta$ is negative.

Hence, the conditions that are true are A, C and D.

Learn more about this concept here:

https://brainly.com/question/1619127

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